How do you check if a given number is prime in Python?

Question

Aryan Kumar · Answer

def is_prime(number):
  if number andlt; 2:
    return False
  for i in range(2, int(number ** 0.5) + 1):
    if number % i == 0:
      return False
  return True
if __name__ == "__main__":
  number = 11
  print(is_prime(number))
This code works by first checking if the number is less than 2. If it is, the function returns False, because no number less than 2 is prime. Otherwise, the function iterates through all the numbers from 2 to the square root of the number, and checks if any of them are factors of the number. If any of them are factors, the function returns False. Otherwise, the function returns True.
Here is an explanation of the code:
The is_prime() function takes a number as its input.The if number andlt; 2: statement checks if the number is less than 2. If it is, the function returns False.The for i in range(2, int(number ** 0.5) + 1): statement iterates through all the numbers from 2 to the square root of the number.The if number % i == 0: statement checks if any of the numbers in the range are factors of the number. If any of them are factors, the function returns False.The return True statement returns True if the number is not divisible by any of the numbers in the range.

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How do you check if a given number is prime in Python?

Utpal Vishwas

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